# How do you graph the inequality #y≥-1/4x+3#?

##### 1 Answer

Oct 11, 2017

See a solution process below:

#### Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

**For:**

**For:**

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-3)^2-0.125)((x-4)^2+(y-2)^2-0.125)((1/4)x+y-3)=0 [-20, 20, -10, 10]}

Now, we can shade the right side of the line.

graph{((1/4)x+y-3) >= 0 [-20, 20, -10, 10]}}